Find the value of (5^0-7^0+2^0)×(5^0+7^0+6^0)
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1
Answer:
3
Step-by-step explanation:
We know that,a⁰= 1
(5⁰-7⁰+2⁰)×(5⁰+7⁰+6⁰)
= (1-1+1)×(1+1+1)
= 1× 3
= 3
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