find the value of (√5+√2)²
![\sqrt{5} + \sqrt{2}² \sqrt{5} + \sqrt{2}²](https://tex.z-dn.net/?f=++%5Csqrt%7B5%7D++%2B++%5Csqrt%7B2%7D%C2%B2)
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by using
- 1st we apply a+b² identity
- as we know a + b² = a² + b² +2ab
- by using this property we get answer as 7 + 2√10
hope it helps you
be brainly
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