Find the value of -(5/2 x^2 y^3)*(2x-y) for x=1 and y=2
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My answer came 0(Too lazy to show the workings)
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please mark a brilliant
Step-by-step explanation:
Quotient = 5y3 + (26/3)y2 + (25/9)y + (80/27)
Remainder = (− 2/27)
Coefficient of y3 = 5
Coefficient of y2 = (26/3)
Coefficient of y = (25/9)
Constant = (80/27
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