Question

find the value of 52c3​

Answer 1

=52c3=52!/(3!*49!)

=(52*51*50)/(3*2*1)

=13260/6

=2210

=10C7=10C3(since nCr=nC(n-r))

=10C3=10!/(3!*7!)

=10*9*8/6

=120

Answer 2

Answer:

The value of 52c3 (52 choose 3) is 23,526.

Step-by-step explanation:

1. Let's start with the nCr formula:      nCr = n! / (r! * (n-r)!)
2. Change the values for n and r as follows:  52c3 = 52! / (3! * 49!)
3. The factorial of 52 is calculated as follows: 52! = 52 * 51 * ... * 2 * 1 = 8.065817e+67
4. The factorial of 3 is calculated as 3! = 3 * 2 * 1 = 6.
5. The factorial of 49 is calculated as follows: 49! = 49 * 48 * ... * 2 * 1 = 6.041526e+64
6. Divide the outcome of step three by the sum of step four's and step five's outcomes: 8.065817e + 67 / (6. (6.041526e+64)) = 23,526

So the value of 52c3 is 23,526.

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