Math, asked by harshrawat36, 1 month ago

Find the value of 53 tan 12° cot 45° cot 60° tan 78º.​

Answers

Answered by khushisuwalka
35

Answer:

= tan 12° cot 38° cot(90° – 38°) cot 60° tan(90° – 12°) = tan 12° cot 38° tan 38° cot 60° cot 12° [∵ cot(90° – θ) = tan θ] = tan12° x 1/tan12° x cot38° x 1/cot38° x cot60°

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