find the value of (55)^3 - (25)^3 - (30)^3.
Answers
Answered by
39
Let a = 55,
b = -25
c = -30
then,
a + b + c = 55 - 25 - 30 = 0
![\implies \: {a}^{3} + {b}^{3} + {c}^{3} = 3abc \\ \\ {(55)}^{3} + {( - 25)}^{3} + {( - 30)}^{3} \implies \: {a}^{3} + {b}^{3} + {c}^{3} = 3abc \\ \\ {(55)}^{3} + {( - 25)}^{3} + {( - 30)}^{3}](https://tex.z-dn.net/?f=+%5Cimplies+%5C%3A+++%7Ba%7D%5E%7B3%7D++%2B++%7Bb%7D%5E%7B3%7D++%2B++%7Bc%7D%5E%7B3%7D++%3D+3abc+%5C%5C+%5C%5C+++%7B%2855%29%7D%5E%7B3%7D++%2B++%7B%28+-+25%29%7D%5E%7B3%7D++%2B++%7B%28+-+30%29%7D%5E%7B3%7D)
= 3(55) (-25) (-30)
= 123750.
b = -25
c = -30
then,
a + b + c = 55 - 25 - 30 = 0
= 3(55) (-25) (-30)
= 123750.
Answered by
13
Hey mate.....
here's ur answer.....
a = 55
B = -30
c = -25
a + B + c
55 - 30 - 25
25 - 25 = 0
==== a^3 + b^3 + c^3 = 3abc....
3(55)(-30)(-25)
![<marquee>= 123750</marquee> <marquee>= 123750</marquee>](https://tex.z-dn.net/?f=%26lt%3Bmarquee%26gt%3B%3D+123750%26lt%3B%2Fmarquee%26gt%3B)
Hope it helps❤❤❤
here's ur answer.....
a = 55
B = -30
c = -25
a + B + c
55 - 30 - 25
25 - 25 = 0
==== a^3 + b^3 + c^3 = 3abc....
3(55)(-30)(-25)
Hope it helps❤❤❤
RiskyJaaat:
hey AaishaG
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