Math, asked by ramavtar79, 11 months ago

find the value of 5a^25-3a^32+2a^-12 for a=1.​

Answers

Answered by Krisshraghuveer
1

Step-by-step explanation:

see in photo

1 power any no. if it is in -ve also the and will be 1

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Answered by SteffiPaul
0

Given,

  • 5a^{25} -3a^{32} + 2a^{-12} is given.
  • a = 1

To find,

  • We have to find the value of 5a^{25} -3a^{32} + 2a^{-12} if a=1.

Solution,

The value of 5a^{25} -3a^{32} + 2a^{-12} for a=1 is 4.

We can simply find the value of 5a^{25} -3a^{32} + 2a^{-12} if a=1 by substituting the value of a = 1 in the given expression.

                       p(a) = 5a^{25} -3a^{32} +2a^{-12}

                       p(1) = 5(1)^{25} -3(1)^{32} +2(1)^{-12}     [a^{-m} = 1/a^m]

                               = 5-3 +2/(1)^{12}

                               = 5-3+2

                               = 4

Value of 5a^{25} -3a^{32} + 2a^{-12} for a=1 is 4.

Hence, the value of 5a^{25} -3a^{32} + 2a^{-12} for a=1 is 4.

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