Find the value of (5a -7b) ^3+(9c-5a)^3+(7b-9c)^3
Answers
Answered by
6
(5a -7b) ^3+(9c-5a)^3+(7b-9c)^3
Using the formula a^3 +b^3+ c^3 = 3abc
(5a -7b) ^3+(9c-5a)^3+(7b-9c)^3 =
3(5a-7b)(9c-5a)(7b-9c)
Using the formula a^3 +b^3+ c^3 = 3abc
(5a -7b) ^3+(9c-5a)^3+(7b-9c)^3 =
3(5a-7b)(9c-5a)(7b-9c)
Answered by
2
Answer:
a^3+b^3+c^3-3abc= (a+b+c)(a^2+b^2+c^2-ab-bc-ca)
but since
a+b+c=0
that is
(5a-7b)+(9c-5a)+(7b-9c)=0
a^3+b^3+c^3=0
a^3+b^3+c^3-3abc=0
a^3+b^3+c^3=3abc
=3(5a-7b)(9c-5a)(7b-9c)
Similar questions