Question

find the value of 5cos²60+4cos²30-tan²45/cos²60+sin²30​

Answer 1

Step-by-step explanation:

5 cos²60 + 4cos²30-tan²45

5×(1/2)²+ 4(√3/2)²- (1)²

5/4 + 3 -1

5/4+2

13/4

Now taking denominator

cos²60 + sin²30

(1/2)² + (1/2)²

1/4 + 1/4

2/4

1/2

Now solving the whole

13/4/1/2

13/4×2

13/2

Answer 2

Answer:

13/2

Step-by-step explanation:

(5 cos² 60 + 4 cos² 30 - tan²45)/(cos² 60 + sin² 30)

$\Rightarrow \frac{5 * (\frac{1}{2})^2 + 4 * (\frac{\sqrt{3}}{2})^2 - (1)^2}{(\frac{1}{2})^2 + (\frac{1}{2})^2}$

$\Rightarrow \frac{5 * (\frac{1}{4}) + 4 * (\frac{{3}}{4}) - (1)}{(\frac{1}{4}) + (\frac{1}{4})}$

$\Rightarrow \frac{ (\frac{5}{4}) + (\frac{{12}}{4}) - (1)}{(\frac{2}{4}) }$

$\Rightarrow \frac{\frac{5 + 12 - 4}{4} }{\frac{2}{4} }$

$\Rightarrow \boxed{\frac{13}{2}}$

Hope it helps!