Find the value of 5x ki power 2 plus 2x minus 222 when x equal to minus 2
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Answer:
Equation x^2+2\sqrt2 kx+18=0x
2
+2
2
kx+18=0
To find : The values of k for which the quadratic equation has equal roots ?
Solution :
The quadratic equation ax^2 + bx + c = 0ax
2
+bx+c=0 has equal roots when discriminant zero,
i.e. b^2 - 4ac = 0b
2
−4ac=0
On comparing,
a=1,\ b=2\sqrt2 k,\ c=18a=1, b=2
2
k, c=18
Substitute the values,
(2\sqrt2 k)^2-4(1)(18)= 0(2
2
k)
2
−4(1)(18)=0
8k^2-72= 08k
2
−72=0
8k^2=728k
2
=72
k^2=\frac{72}{8}k
2
=
8
72
k^2=9k
2
=9
k=\sqrt{9}k=
9
k=\pm 3k=±3
Therefore, The value of k is 3 and -3.
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