Question

find the value of 5y^3+y-3/y-1

Answer 1

Answer:

The equation are

3x+5y−3=0

6x+ky−8=0

Here, a

1

=3,b

1

=5,c

1

=−3

and a

2

=6,b

2

=k,c

2

=−8

Given, the system of equation has no solution

⇒

a

2

a

1

=

b

2

b

1



=

c

2

c

1

⇒

6

3

=

k

5



=

−8

−3

⇒k=10