Math, asked by prikshitkundal0, 16 days ago

find the value of (6 ‐¹ +(3/2) ‐¹ is​

Answers

Answered by biswajithemram753
0

Answer:

Step-by-step explanation:

To find the value of (6 ‐¹ +(3/2) ‐¹, we need to calculate the reciprocal of 6 and the reciprocal of 3/2 and add them together. The reciprocal of a number a is 1/a, so the reciprocal of 6 is 1/6 and the reciprocal of 3/2 is 2/3. Adding these together, we get:

(6 ‐¹ +(3/2) ‐¹ = 1/6 + 2/3

= (1 + 2)/6

= 3/6

= 0.5

So, the value of (6 ‐¹ +(3/2) ‐¹ is 0.5.

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