Question

find the value of 6/3√2-2√3

Answer 1

6/(3√2-2√3)

Rationalising the denominator we have,

6 (3√2+2√3)
----------------×----------------
(3√2-2√3) (3√2-2√3)

18√2+12√2
------------------
(3√2)²-(2√3)²

(18+12)√2
--------------
18-12

30√2
---------
6

=5√2 Ans.

Answer 2

Heya !!

$\frac{6}{3 \sqrt{2} - 2 \sqrt{3} }$

On rationalizing the denominator we get,

$= \frac{6}{3 \sqrt{2} - 2 \sqrt{3} } \times \frac{3 \sqrt{2} + 2 \sqrt{3} }{3 \sqrt{2} + 2 \sqrt{3} } \\ \\ = \frac{6(3 \sqrt{2} + 2 \sqrt{3} ) }{ {(3 \sqrt{2}) }^{2} - {(2 \sqrt{3} )}^{2} } \\ \\ = \frac{18 \sqrt{2} + 12 \sqrt{3} }{18 - 12} \\ \\ = \frac{18 \sqrt{2} + 12 \sqrt{3} }{6} \\ \\ = 3 \sqrt{2} + 2 \sqrt{3}$

Hope this helps ☺