Question

Find the value of:
(6.4)² – (5.4)^2 / (8.9)^2+(8.9) (2.2)+(1.1)^2​

Answer 1

Step-by-step explanation:

$\frac{ {6.4}^{2} - {5.4}^{2} }{ {8.9}^{2} + (8.9)(2.2) + {1.1}^{2}} = > \frac{(6.4 + 5.4)(6.4 - 5.4)}{ {(8.9 + 1.1)}^{2} }$

${(x + y)}^{2} = {x}^{2} + {y}^{2} + 2xy$

$= > \frac{11.8 \times 1}{100} = > 0.118$

Hope it helps you.

Answer 2

$\frac{(6.4)^2-(5.4)^2}{(8.9)^2+(8.9) (2.2)+(1.1)^2}=0.118$

Step-by-step explanation:

Given : Expression $\frac{(6.4)^2-(5.4)^2}{(8.9)^2+(8.9) (2.2)+(1.1)^2}$

To find : The value of expression ?

Solution :

Re-write expression as,

$=\frac{(6.4)^2-(5.4)^2}{(8.9)^2+2(8.9) (1.1)+(1.1)^2}$

Applying algebraic identity,

$a^2-b^2=(a+b)(a-b)\\(a+b)^2=a^2+b^2+2ab$

$=\frac{(6.4+5.4)(6.4-5.4)}{(8.9+1.1)^2}$

$=\frac{(11.8)(1)}{(10)^2}$

$=\frac{11.8}{100}$

$=0.118$

Therefore, the value of the expression is $\frac{(6.4)^2-(5.4)^2}{(8.9)^2+(8.9) (2.2)+(1.1)^2}=0.118$.

#Learn more

8.5 - (4.07 -1.2 - 0.9) of 1.6​

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