Question

Find the value of (-6)4 + 32
$( - 6) {}^{4} + 3 {}^{2}$
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Answer 1

Question:-

${( - 6)}^{4} + {3}^{2}$

Solution:-

$( { - 6})^{4} = - 6 \times - 6 \times - 6 \times - 6 = 1296$

$({3})^{2} = 3 \times 3 = 9$

$= 1296 + 9$

$= 1305$