Question

find the value of √6+√6+ √6............​

Answer 1

Answer:

Letx=

6+

6+

6+

6+...∞

On squaring both sides,

x

2

=6+

6+

6+

6+

6+...∞

x

2

=6+x

x

2

−x−6=0

x=

2(1)

1±

1

2

−4×1×(−6)

x=

2

1±

25

=

2

1±5

∴x=3 or x=−2

Since a negative number cannot be under root, hence x=3

Answer 2

Step-by-step explanation:

Answer :

..................................

$\sqrt{6} + \sqrt{6} + \sqrt{6} ..............x$

$x \: is \: repeating$

$\sqrt{6} + x = x$

.

$\sqrt{6} + x = x$

.

$6 + {x}^{1} = {x}^{2}$

.

$6+x=x²$

.

6+x-x²=0

x²-x-6=0

x²-3x+2x-6=0

x=3 and x=-2

$\longrightarrow$ Answer will be 3,and-2