find the value of√6+√6+√6+••••
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X=3
Let x=√6+√6+√6+√6+......
On squaring both sides,
x²=6+√6+√6+√6+√6......
x²=6+x
x²-x-6=0
x=1±√1²-4×1×(-6)
2(1)
x=1±√25 = 1±5
2 2
x=3 or x=-2
- Since a negative number can't be under root,hence x=3
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