Question

Find the value of 6 tan² thita - 6 / cos ² thita by completing the following activity.
6 tan² thita - 6 / cos²thita
= 6 ( tan²thita - 1 / _____ )
= 6 ( tan²thita - ______ )
= ( 1 / cos thita = sec thita )
= 6 ( ____ ) = _____ ​

Answer 1

answer= -6

Step-by-step explanation:

$6( \tan^{2}thita -1 \div square)$

$6( \tan^{2}thita - square)$

$(1 \div \cos \: thita = \sec \: thita)$

$6( - 1)$

$= - 6$