Question

find the value of 6 tan²theta -(6/tan²theta).​

Answer 1

Answer

$\tan \: theta = \frac{ \sin \: theta }{ \cos \: theta} \\ 6 \times \frac{ {sin \: }^{2} theta}{ { \cos }^{2}theta } - \frac{6}{ { \cos }^{2}theta } \\ \frac{6 { \sin }^{2} - 6 }{ { \cos }^{2}theta } \\ \frac{6( { \sin }^{2}theta - 1) }{ { \cos }^{2}theta } = \frac{6 \times - { \cos }^{2} theta}{ { \cos }^{2} theta} \\ { \sin}^{2} theta + { \cos }^{2} theta = 1 \\ { \sin }^{2} theta - 1 = { - \cos}^{2} theta \: \\ ans = - 6$

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