Find the value of 60% of 180 days.
Answers
Answered by
1
ANSWER
Radioactive reactions follow first order kinetics. Half-life period of a reaction is the time required for the reaction to be half completed.
Amount of substance left unreacted after one half life= 2[A]0
where, [A]0 is initial concentration.
Amount of substance left after two half lives= 22[A0]
In general,
Amount of substance left unreacted after nhalf lives= 2n[A0]
Now, Half life of 53I125=60 days
Total time= 180 days
No. of Half lives= 60180=3
So, amount of reactant left unreacted after 3half lives= 23[A]0
=8[A]0
% left= [A]0[A0]/8×100%
=81×100%=12.5%
Answered by
1
Answer:
here is your answer
=60°/°×180
=60/100×180
=6×18
=108 days.
Similar questions