Find the value of 64 x cube minus 125 y cube if 4 x minus 5 Y is equal to 16 and xy is equal to 12
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SOLUTION:-
here,
4x-5y =16 and xy=12
we know that
a3-b3 = (a-b)(a2+ab+b2)
again,
(a-b)2 +3ab=a2-2ab+b2+3ab
(a-b)2+3ab=a2+ab+b2
so,
a3-b3=(a-b)[(a-b)2+3ab]
here,
we use the above formula for solving the equation,
now,
(4x-5y)2=(16)2=256
34x×5y=60xy=60×12=720
hence,
64x3-125y3=(4x)3-(5y)3
=(4x-5y)[(4x-5y)2+60xy]
=16×(256+720)
=16×976
=15616
64x3-125y3=4672
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