Find the value of 64 x cube minus 125 z cube, if 4x minus 5z is equal to 16 and xz is equal to 12
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Answered by
1
Answer:
64x^3-125z^3
=(4x)^3-(5z)^3
=(4x-5z)^3+3×4x×5z(4x-5z)
=16^3+60×12×16
=4096+11520
=15616 ans.
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Answered by
1
64x^3-125z^3
=(4x)^3-(5z)^3
=(4x-5z)^3+3×4x×5z(4x-5z)
=16^3+60×12×16
=4096+11520
=15616 ans.
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