Math, asked by Adityapsingh2601, 1 year ago

Find the value of 64a^3 – 27b^3 – 180ab – 5, when 4a – 3b = 5

Answers

Answered by anjali1738
5

Answer:

4a-3b=5

cubing both sides

(4a-3b)^3=5^3

64a^3-27b^3-3*4a*3b(4a-3b)=125

64a^3-27b^3-36ab*5=125

64a^3-27b^3-180ab=125

ANS 125

Answered by Anonymous
1

Answer:

125

Step-by-step explanation:

4a-3b=5

By cubing both sides

(4a-3b)^3=5^3

64a^3-27b^3-3*4a*3b(4a-3b)=125

64a^3-27b^3-36ab*5=125

64a^3-27b^3-180ab=125

ans =125

mark brainlest

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