Question

Find the value of 64x3 + 27y3, if:
(i) 4x + 3y = 4 and xy = 2​

Answer 1

Step-by-step explanation:

58 is the answer. See attached picture for the answer to the question. Please mark me brainliest

Answer 2

Answer:

The value is 58.

Step-by-step explanation:

As per the data given in the question

We have to calculate the value of $64x^{3}+27y^{3}$

As per the questions

It is given that

4x+3y=4 and xy=2

First we have to distribute of $64x^{3}+27y^{3}$ in to $x^{3}+y^{3}$ form

then $64x^{3}+27y^{3}=4x^{3}+3y^{3}$

As we know that $x^{3}+y^{3}=(x+y)^{3}-3xy$

so, we have to put x=4x and y=3y

so solution will be

= $(4x+3y)^{3}-3*4x*3y$

= $4^{3}$-3*2

= 64-6

=58

Hence, the value is 58.

For Such type of question:

https://brainly.in/question/27066819

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