Find the value of (6a²b⁵)×(2a³b²),when a=1and b=2
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Answer: (6×1×1×2×2×2×2×2) ×(2×1×1×1×2×2)
(6×1×32) ×(2×1×4)
192×8
1536
Answered by
0
Answer:
1536
Step-by-step explanation:
(6a²b⁵)×(2a³b²)
=(6×1²×2⁵)×(2×1³×2²)
=(6×1×32)×(2×1×4)
=192×8
=1536
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