find the value of 6ab-7bc+9abc if a=-1,b=2,c=3
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Answer:
5b−4c+a+2c−3b−4a=−2c+2b−3a
a+2b−3c+2c−3b−4a=−3s−b−c
(−2c+2b−3s)−(−3a−b−c)
−2c+2b−3a+3a+b+c
=3b−c
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