Math, asked by VenkiDOP9204, 5 days ago

Find the value of 6ab2+4b2+a3
When a=-2, b=4

Answers

Answered by IIMagicalWorldII
6

a = 2 \: b = 4 \\ 6ab2 + 4b2 + a3 \\ 6(2)(4)2 + 4(4)2 + (2)3 \\  = 56 + 32 + 6 \\  = 94

Answered by u627
0

Answer:

96+32+6=134

6×2×4×2+4×4×2+2×3=134

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