Question

find the value of
6tan^2 thita-6÷cos^2 thita

​

Answer 1

Answer:

-6

Step-by-step explanation:

$sec ^{2} \alpha - {tan}^{2} \alpha = 1$

so

$6\tan {}^{2} ( \alpha ) - \frac{6}{ \cos {}^{2} ( \alpha ) } = 6\tan {}^{2} ( \alpha ) - {6}{ \ \sec {}^{2} ( \alpha ) } = - 6$