find the value of × (7/4)-6×(7/4)-4=(7/4)2×
Answers
Answered by
8
Answer:
Multiple: 6 * 7/
4
= 6 · 7/
1 · 4
= 42/
4
= 21 · 2/
2 · 2
= 21/
2
Multiply both numerators and denominators. Result fraction keep to lowest possible denominator GCD(42, 4) = 2. In the next intermediate step, , cancel by a common factor of 2 gives 21/
2
.
In words - six multiplied by seven quarters = twenty-one halfs.
Step-by-step explanation:
(7/4)-6×(7/4)-4=(7/4)*2× = = 0 Ans
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Answer:
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