Question

find the value of 7 x-2=1​

Answer 1

Answer:

7x3+8x−x37−x8

=7(x3−x31)+8(x−x1)

=7(x−x1)(x2+x21+1)+8(x−x1)

Now,

(x−x1)2=x2+x21−2(x)(x1)

                      =7−2

                      =5

=>x−x1=±5

Putting the values we get,

=7(±5)(7+1)+8(±5

Answer 2

Answer:

7x - 2 = 1

7x = 1 + 2

7x = 3

x = 3/7