Question

Find the value of 7x^2+3xy+y^2 when x=3 and y=[-3]

Answer 1

=7*3*3+3*3*(-3)+(-3)*-3
=63-27+9
=72-27
=45

Answer 2

X=3

y=-3

7x²+3xy+y²

7(3)²+3(3)(-3)+(-3)²

7(9)+3(-9)+(9)

63-27+9

72-27

==45