Math, asked by sanchitaherwade7, 1 month ago

Find the value of (8/27)⅓

Answers

Answered by samson283
1

Answer:

\frac{2}{3} =0.6 or \frac{8}{27}×\frac{1}{3}=\frac{8}{81}

Step-by-step explanation:

(\frac{8}{27} )^\frac{1}{3} \\=\frac{8^\frac{1}{3} }{27^\frac{1}{3} } \\

simplify the numerator

rewrite 8 as 2³

=(\frac{(2^3)^\frac{1}{3} }{27^\frac{1}{3} }

apply the power rule

(a^m)^n=a^m^n

so ,  

=\frac{2^3^(\frac{^1}{^3})}{27^\frac{1}{3} }

cancel the common factor 3 i.e 3×1/3=1

=\frac{2^1}{27^\frac{1}{3} }

evaluate the exponent

=\frac{2}{27^\frac{1}{3} }

simplify the denominator

apply the power rule

(a^m)^n=a^m^n

=\frac{2}{(3^3)^\frac{1}{3} }

therefore , 3×1/3=1

=\frac{2}{3^1}

=\frac{2}{3} \\

=0.6

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