Math, asked by adityatanwar321, 5 months ago

Find the value of (8⁰+5⁻¹)⁻² × 3²

Answers

Answered by CloseEncounter
10

Find the value of (8⁰+5⁻¹)⁻² × 3²

(8⁰+5⁻¹)⁻² × 3²

\bold{(1+{\dfrac{1}{5})^{-2}×3²}}

\bold{\dfrac{5+1}{5}}^{-2}×3²

\bold{\dfrac{6}{5}}^{-2}×3²

\bold{\dfrac{5}{6}}^{2}×3²

\bold{\dfrac{25}{36}}×3²

\bold{\dfrac{25}{36}}×9

\bold{\dfrac{25}{36}}×9

\bold{\dfrac{25}{4}}

hope it helps ☺️

Answered by Anonymous
0

Given : The given problem is, (8⁰+5⁻¹)⁻² × 3²

To find : Answer to the given problem.

Solution :

We can simply solve this mathematical problem by using the following mathematical process. (our goal is to calculate the answer to the given problem)

Here, we will be using general rules of exponent. (using these rules are necessary in this case)

So,

= (8⁰+5⁻¹)⁻² × 3²

 =  {(1 +  \frac{1}{5} )}^{ - 2}  \times  {3}^{2}

 =  {( \frac{5 + 1}{5} )}^{ - 2}  \times  {3}^{2}

 =   {( \frac{6}{5}) }^{ - 2}  \times  {3}^{2}

 =  \frac{1}{  {( \frac{6}{5})}^{2} }  \times  {3}^{2}

 =  \frac{1}{ \frac{36}{25} }  \times 9

 = 1 \times \frac{25}{36}  \times 9

 =  \frac{25}{4}

 = 6.25

(This will be considered as the final result of the given mathematical problem.)

Used formula :

  • x⁰ = 1
  •  {x}^{ - 1}  =  \frac{1}{x}

Hence, the answer is, 6.25

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