Math, asked by lekhashrism, 8 months ago

find the value of 8 sin2x cosx cotx when x=45°​

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Answered by amitsnh
0

8 sin 2x cos x cot x

= 8 sin 2*45° cos 45° cot 45°

= 8 sin 90° cos 45° cot 45°

= 8 x 1 x (1/√2) x 1

= 4√2

Answered by Anonymous
2

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