Math, asked by lekhashrism, 6 months ago

find the value of 8 sin2x cosx cotx when x=45°​

Answers

Answered by amitsnh
0

8 sin 2x cos x cot x

= 8 sin 2*45° cos 45° cot 45°

= 8 sin 90° cos 45° cot 45°

= 8 x 1 x (1/√2) x 1

= 4√2

Answered by Anonymous
2

Answer:

Hope it helps you.. Mark me as brainliest

Attachments:
Similar questions