find the value of 8 x cube + 27 y cube is 2 x + 3 Y = 28 and xy = 2
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3y^3+ 2x^3= (3y+2x)(3y^2-3y×2x+2x^2)
= 28×2(3y^2+2x^2)
= 56(3y^2+2x^2)
= 168y^2 + 112x^2
= 28×2(3y^2+2x^2)
= 56(3y^2+2x^2)
= 168y^2 + 112x^2
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When y=-2then value is - 224and when y=-2/3then value is 208
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