Math, asked by nehaautomobiles9, 6 months ago

Find the value of -(8 x²y ^3)×(1\5xy^2)when x=-1 and y=2

Answers

Answered by kanishkaverma1952

2

Answer:

-(8x²y³) ×(1/5xy²)

-8x²y³/5xy²

-8xy

-8(-1)(2)

16

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