Math, asked by minsangvaiphei81, 1 year ago

find the value of(81)0.16×(​

Answers

Answered by maabhiramanil1157
1

Step-by-step explanation:

By law of exponents [aⁿ × aˣ = a⁽ⁿ ⁺ ˣ⁾] = 81^(0.16 + 0.09) = 81^(0.25) (3⁴)^0.25. [81 = 3 ×3×3×3 = 3⁴] = (3)^{4 × 0.25}

[(aⁿ)ˣ = aⁿˣ] = (3)¹ = 3.

Hence, the value is 3. HOPE THIS ANSWER WILL HELP YOU...

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