Math, asked by kumarpawan9443, 1 month ago

find the value of 88^2-87^2+86^2-85^2+84^2-83^2

Answers

Answered by bagkakali
5

Answer:

88^2-87^2+86^2-85^2+84^2-83^2

=(88+87)(88-87)+(86+85)(86-85)+(84+83)(84-83)

=175×1+171×1+167×1

=175+171+167

=513

Answered by ProchatGhatak660
0

ANSWER :

513 ( FASTEST ANSWER)

EXPLAINATION :

(BEST FASTEST WAY)

88^2-87^2+86^2-85^2+84^2-83^2 = __?__

STEP : 1)

MAKING PAIRS LIKE -- 88 & 87 , 86 & 85 , 84 & 83

NOTE: OTHER PAIRS WOULD NOT BE USED

STEP: 2)

(88 + 87 ) = 175 , EACH PAIR DIFFERENCE = 1

= > (175 × 3 × 1) - ( 2 × 2 + 2 × 2 +2 × 2)

= > 525 - (4 + 4 + 4)

= > 525 - 12

= > 513 ( BRILLIANT ANSWER )

( BY USING VBODMAS LAW OF MATHEMATICS )

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