Question

find the value of (-8b^2+4b-8)+(-2b^2-5b-1), when b= ?​

Answer 1

Answer:

Step-by-step explanation:

a + b = 6 …………….. (1)

ab = 8 …………………(2)

a = 6 - b ……………….(using 1)

Substituting ‘a’ in (2)

(6-b)b = 8

- b^2 + 6b = 8

- b^2 + 6b -8 = 0

b^2 - 6b + 8 = 0 …………………(taking (-1) common)

Method 1

b^2 - 2b - 4b + 8 = 0

b(b-2) - 4(b-2) = 0

(b-2)(b-4) = 0

b - 2 = 0

b = 2

a = 6 -2

a = 4

b - 4 = 0

b = 4

a = 6 - 4

a = 2

Answer 2

Answer:

Hope this helped you!!