Question

find the value of (-8b^2+4b-8)+(-2b^2-5b-1), when b= ?​

Answer 1

Step-by-step explanation:

$\sf{\underline{\underline{\large{\bold{Answer:-}}}}}$

-8b²+4b-8-2b²-5b-1

-10b²-b-9

10b²+b+9=0

10b²+10b-9b+9=0

10b(b+1)-9(b+1)=0

b=9/10

b=-1