Question

FIND THE VALUE OF 8sec²60º-8tan²60º​

Answer 1

Answer:

-1

Step-by-step explanation:

Answer :

-1

Solution :

sec610∘cosec160∘−cot380∘tan470∘sec610∘cosec160∘-cot380∘tan470∘

=sec(720∘−110∘)cosec(180∘−20∘)=sec(720∘-110∘)cosec(180∘-20∘)

−cot(360∘+20∘)tan(360∘+110∘)-cot(360∘+20∘)tan(360∘+110∘)

=1cos110∘.1sin20∘−cot20∘tan110∘=1cos110∘.1sin20∘-cot20∘tan110∘

=−1sin220∘+cot220∘=-1sin220∘+cot220∘

=−[cosec220∘−cot220∘]=-[cosec220∘-cot220∘]

=−1

Answer 2

Answer:

98+-$!#/(@(;"!!@)*!;+(#++$9(+$+(#