Math, asked by pavithrans, 3 months ago

Find the value of 8sin2x cos4x sin6x, when x = 15° ​

Answers

Answered by sujathavin
1

Answer:

2

Step-by-step explanation:

GIVEN: X=15° ​

TO FIND: 8sin2x cos4x sin6x =?

SOLUTION:

8 sin30.cos60.sin90°[substituting value of sin&cos

8[1/2]. [1/2] .1

=2

note: sin 30°=1/2 , cos60°= 1/2 & sin90°=1

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Answered by shilshaurya5606
1

Answer:

Addition - 5.5

Multiplication - 2

Subtraction - 2.5

Division - 8

Step-by-step explanation:

As there are no math symbols specified here, I am going to write the solution for all symbols.

Values:-

8sin2x = 8sin2(15)° => 8sin30°

=> 8(1/2) => 4

cos4x = cos4(15)° => cos60°

=> 1/2

sin6x = sin6(15)° => sin90°

=> 1

Now, putting these values in all equations with different symbols.

Addition:

8sin2x + cos4x + sin6x

=> 4 + 1/2 + 1 => 5.5

Multiplication:

8sin2x*cos4x*sin6x

=> 4*(1/2)*1 => 2

Subtraction:

8sin2x - cos4x - sin6x

=> 4 - (1/2) - 1 => 2.5

Division:

8sin2x cos4x sin6x

=> 4 ÷ (1/2) ÷ 1

=> 4 ÷ 1/2 => 8

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