Question

Find the value of 8sin2x.cos4x.sin6x,whenx=15

Answer 1

hey mate

here is your answer

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$here \: given \: that \\ the \: value \: of \: : x = 15 \\ 8 \: sin \: 2x \times cos \: 4x \times sin \: 6x \\ \\ if \: we \: put \: the \: value \: of \: \: \: x \\ then \\ 8 \: sin \: (2 \times 15).cos \: (4 \times 15).sin \: 6 \times 15 \\ = 8 \: sin \: 30.cos \: 60.sin \: 90 \\ = 8 \: sin30.cos(90 - 30).sin90 \\ = 8 \: sin30.sin30.1 \\ (the \: value \: of \: sin90 = 1) \\ = 8 \times \frac{1}{2} \times \frac{1}{2} \times 1 \\ (the \: value \: of \: sin \: 30 = \frac{1}{2} ) \: \\ = \frac{8}{4} \\ = 2$

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the answer is 2⃣ ✔✔✔✔✔

✨✨hope it helps✨✨