Question

find the value of (-8x^2y^2)×(1/5xy^2).when x=-1 and y=2​

Answer 1

Step-by-step explanation:

by put the value of x and y we get equation like

[-8(-1)^2 2(2)^2] × [1/5 (-1)(2)^2]

(-8×1×2×4) ×(1/5×-1×4)

-64×-4/5

256/5

Answer 2

Step-by-step explanation:

substitute x=-1 and y=2,

= (-8(-1)^2(2)^2) × (1/5(-1)(2)^2)

= -8(1)(4) × 1/5(-1)(4)

= 32 × -4/5

= -128/5 = 25.6

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