Question

Find the value of 8x^3-27y^3-18xy(2x-3y) when x=8,y=5​

Answer 1

Answer: 1

Step-by-step explanation:

Instead of substituting the values of x and y directly let's simplify it.

So , the equation given here is

8x^3 - 27y^3 - 18xy( 2x - 3y )

(2x)^3 - (3y)^3 - (3(2x)(3y))(2x - 3y )

This is in the form of

a^3 - b^3 - 3ab(a - b) where a = 2x and b = 3y

This is the formula for ( a - b )^3

So , we get it as , ( 2x - 3y )^3

Now let's substitute the values

we will get the answer without any

confusion. It's given that x = 8 and. y = 5.

So we get ,

=> ( 2(8) - 3(5))^3

=> ( 16 - 15 )^3

=> ( 1 )^3

=> 1

Therefore the required answer is 1.

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