find the value of 8x^3+27y^3 if 2x+3y=8 and xy=2
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2X+3Y = 8
8X³+27Y³ = (2X)³+(3Y)³
= (2X+3Y) × ((2X)²–2X×3Y+(3Y)²)
= 8 × ((2X+3Y)²–2×2X×3Y–6XY)
= 8 × (8²–18×2)
= 8×(64–36)
= 8×28
= 224
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