find the value of 8x^3+y^3-30xy+125 if 2x+y=-5
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Question:to find value of 8x3+y3-30xy+125
Given: 2x+y = -5
Answer:By using the identity (a+b)3=(a)3+(b)3+3ab[a+b]
=8x3+y3-30xy+125
=(2x)3+(y)3+3(2x)(y)[2x+y] +125
= (2x+y)3+125
= -125+125
= 0 - Answer
Given: 2x+y = -5
Answer:By using the identity (a+b)3=(a)3+(b)3+3ab[a+b]
=8x3+y3-30xy+125
=(2x)3+(y)3+3(2x)(y)[2x+y] +125
= (2x+y)3+125
= -125+125
= 0 - Answer
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are answer zero ho Jayega samagh mai aa gya hoga
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