Question

find the value of 8x^3+y^3 , if 2x+y =3 and xy = 1​

Answer 1

Answer:

FIRSTLY IT MEANS THAT ITS VALUE IS (8x+y)^3 and. then apply identity (a+b)^3= a^3+b^3+3ab(a-b)

now apply values in given place

=(8x+y)^3= 8x^3+y^3+3×8x×y(8x-y)

=512x^3+y^3+24xy(8x-y)

as given here, xy =1

512x^3+y^3+24×1=24(8x-y)

512x^3+y^3+192x-24y

Step-by-step explanation:

according to me I think it's wrong but somehwere it may be right