find the value of (8x²y²)×(1/5xy²)when x=-1 and y=2
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[8×(-1)²×(2)²] × [1/5×(-1)×(2)²
8×1×4 × 1/5×(-1)×4
32 × 1/5× (-4)
-128/5
-25.6
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