Math, asked by ljerald53, 14 days ago

find the value of (8x²y²)×(1/5xy²)when x=-1 and y=2​

Answers

Answered by mohammadkaif7643
2

Answer:

[8×(-1)²×(2)²] × [1/5×(-1)×(2)²

8×1×4 × 1/5×(-1)×4

32 × 1/5× (-4)

-128/5

-25.6

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