Question

Find the value of 8xy(x2+y2)if x+y=5and X-y=1

Answer 1

Answer:

Multiply (1) and (2) to get (x^2-y^2) = √15

Add (1) and (2) to get 2x = (√5 + √3) …(3)

Subtract (2) from (1) to get 2y = (√5 - √3) …(4)

Therefore, 8xy(x^2-y^2) = 2*2x*2y*(x^2-y^2)

= 2*(√5 + √3)*(√5 - √3)*√15

= 2*2*√15

= 4√15. Answer

Answer 2

Answer:

the correct answer is x+y=0